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Fourier Synthesis and the Phase Problem

Single-crystal data

A diffraction pattern gives intensities, and correcting those gives |F|2, so amplitudes. The phases are never recorded at all, and the page opens by saying what that costs. This sums a real structure both ways, so you can see what the missing half was carrying.

Before this
A structure factor has an amplitude and a phase, and only the first survives a measurement. If that is not yet concrete, build one first.
You supply
One of the named structures, and how far the series should run. Everything else — the coefficients, their signs, the electron count — is computed from the atoms.
Reading it
Summing over h alone gives the density projected down b and c, not a section — atoms sharing an x land on top of one another. And a truncated series rings: it merges neighbours the resolution cannot separate, and can dip below zero between the atoms.

Worked examples: zirconia — 7 of 12 signs negative · aragonite, alternating signs · quartz at 6 terms — the silicons merge · quartz at 30 terms — and separate · caesium chloride — where the demonstration is empty

Earlier on the path: Structure Factor Calculator Next on the path: The Patterson Function On From intensities to a structure, step 2 of 6

Notation here: F, |F| — what each one means here

See also: Structure Factor Calculator · The Patterson Function · Difference Map

What each input changes
Terms
How many reflections the sum runs over — the resolution of the map. Too few and two atoms merge into one peak, which is a limit of the DATA and not of the method.
Teaching with this page
Objective
After this page a learner can state the phase problem precisely and show what a correct set of amplitudes with wrong phases produces.
Start from
this worked example
Ask first
A synthesis from six terms shows a maximum where the structure has no atom. Is the structure wrong?
Watch for
“Yes — density appears where the electrons are”
Then
The Patterson Function
Check yourself: A synthesis from six terms shows a maximum where the structure has no atom. Is the structure wrong?

No — a series cut short has ripples of its own Yes — density appears where the electrons are

The density is a sum over all reflections and any measurement supplies a finite number of them. Stopping at six is multiplying the true transform by a box, and a box in one space is a ripple in the other — so features appear beside real atoms and between them. Adding terms shrinks them and no number of terms removes them. Add some here and watch it happen.

Input

up to h =

How far the series runs. Blank means 12. Fewer terms is lower resolution — the peaks broaden and neighbouring atoms merge.

Gaps in the row of bars are systematic absences: a centred lattice or a glide plane makes whole classes of h00 vanish, so the series has fewer terms than its length suggests and the projection repeats more often than the cell does.

The half a measurement throws away

A diffraction experiment records intensities — counts under each reflection. Correcting those for geometry, polarisation and absorption gives |F|2, and its square root is |F|, the amplitude of that reflection; the corrections page is that step on its own. The electron density is the Fourier transform of the structure factors — so with the amplitudes and the phases, the structure follows by summation, and there is nothing left to solve. No step of that chain records a phase. Recovering them is the central problem of the subject.

Choose a structure and this sums its F(h00) into the electron density projected along a, then does it again with every phase set to zero — which is what you would have if you used the measurement alone.

For some of the named structures the second sum is identical to the first. That is a result rather than an omission, and the page says which ones and why.

Try it

zirconia — 7 of 12 signs negative · aragonite, alternating signs · quartz at 6 terms — the silicons merge · quartz at 30 terms — and separate · caesium chloride — where the demonstration is empty

Where this comes from