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Wilson Plot and E Statistics

The evidence systematic absences cannot give. A centre of inversion forces every phase to 0 or 180°, which leaves a mark on the distribution of the intensities rather than on which of them are missing — so it is measurable exactly where the determination runs out. The same shell averages give the Wilson plot, whose slope is the overall temperature factor.

You supply
One of the named structures. A full set of reflections is computed from its atoms, so nothing has to be measured — and an overall B can be added to see the plot tilt.
Reading it
Wilson's derivation assumes many atoms of comparable scattering power sitting at random. A structure whose atoms are all on special positions has no free coordinates at all, so the statistic means nothing there — and the page refuses a verdict rather than giving the wrong one.

Worked examples: albite, 52 atoms in the cell — centrosymmetric · quartz, no centre of inversion · cristobalite — the same, from different symmetry · albite with an overall B of 3 Ų · rutile — where the test does not apply · berlinite — where the test is confidently wrong

Input

Ų

Added to every atom. Leave it blank for stationary atoms — then put a value in and watch the plot tilt, because the temperature factor is the only thing in the calculation that makes it do so.

Systematic absences see the centring, the glide planes and the screw axes, and they cannot see a centre of inversion: a centrosymmetric group and its non-centrosymmetric subgroups extinguish exactly the same reflections. That is why the determination hands back a family of groups, and this statistic is the independent evidence that separates them.

No verdict

This structure cannot be judged this way, and the number below is printed only so that you can see it is not to be believed.

Every atom in this structure sits on a special position, so the symmetry fixes all of its coordinates — there are no free parameters for the statistics to describe. Wilson's derivation puts atoms at random in the cell; here nothing is random, |F| takes a few determined values instead of a distribution, and the number below is not evidence about a centre of inversion. Rutile is the case worth trying: it is centrosymmetric and the statistic points the other way.

⟨||E|2 − 1|⟩ = 0.828, where the space group P42/mnm does contain a centre of inversion.

|E|2 is an intensity divided by the mean of its own shell, so it says how strong a reflection is for its resolution and the fall-off is already gone. A centre of inversion forces every phase to 0 or 180°, which spreads the intensities wider than random phases do: ⟨||E|2 − 1|⟩ is 0.968 with a centre and 0.736 without one.

The Wilson plot

0.000.171.20 Å0.350.85 Å0.520.69 Å0.690.60 Å0.150.200.250.31shell at 1.55 A, 16 reflections, ln ratio 0.291shell at 0.96 A, 23 reflections, ln ratio 0.258shell at 0.75 A, 29 reflections, ln ratio 0.161shell at 0.64 A, 30 reflections, ln ratio 0.282(sin θ / λ)² and the corresponding dln (〈I〉 / 〈Σf₀²〉)

B = 0.04 Å² from the slope, over 4 resolution shells.

Each point is one resolution shell: the mean intensity divided by the mean of Σf02, which is what the shell would scatter with stationary atoms. The ratio falls as exp(−2B s2), so the logarithm is a straight line and its slope is −2B. The temperature factor is the only thing in the calculation that makes it tilt. The recovered value carries a small offset of its own, because Wilson's derivation assumes atoms at random and a real structure is not random; what tracks the temperature factor exactly is the change in the slope, so put in two different values and compare.

What was measured

Space group P42/mnm, order 16
Atoms in the cell6
Effective scatterers 4.72
Scattering from general positions 0%
Unique reflections 98 to 0.60 Å
Resolution shells4
⟨|E|2 1.000
|E| > 1 44.9%
|E| > 2 0.0%
|E| > 3 0.0%

The effective count is (Σf)² / Σf²: it equals the atom count when every atom is the same element and falls below it as one atom starts to dominate, which is what Wilson's “atoms of comparable scattering power” is asking for.

The tails have ideal values too, but a synthetic data set this size holds only a handful of reflections above |E| = 2 and none above 3 for most structures, so they describe the distribution here without deciding anything. The mean deviation above is what the verdict rests on.

Try it

albite, 52 atoms in the cell — centrosymmetric · quartz, no centre of inversion · cristobalite — the same, from different symmetry · albite with an overall B of 3 Ų · rutile — where the test does not apply · berlinite — where the test is confidently wrong